02Class 11 Physics

Motion in a Straight Line formulas

The equations of motion and graph rules for Motion in a Straight Line. Nearly all of this chapter comes down to choosing a sign convention and sticking to it.

Definitions

Average velocity
vˉ=ΔxΔt\displaystyle \bar v = \frac{\Delta x}{\Delta t}
Instantaneous velocity
v=dxdt\displaystyle v = \frac{dx}{dt}
Instantaneous acceleration
a=dvdt=vdvdx\displaystyle a = \frac{dv}{dt} = v\frac{dv}{dx}

Equations of motion (constant acceleration)

First equation
v=u+at\displaystyle v = u + at
Second equation
s=ut+12at2\displaystyle s = ut + \tfrac12 at^2
Third equation
v2=u2+2as\displaystyle v^2 = u^2 + 2as
Distance in the nth second
sn=u+a2(2n−1)\displaystyle s_n = u + \frac{a}{2}(2n - 1)

Free fall and graphs

Falling from rest
v=gt,h=12gt2,v2=2gh\displaystyle v = gt, \quad h = \tfrac12 gt^2, \quad v^2 = 2gh
Relative velocity
vBA=vB−vA\displaystyle v_{BA} = v_B - v_A
Reading graphs
v=slope of x-t,a=slope of v-t,Δx=area under v-t\displaystyle v = \text{slope of } x\text{-}t, \quad a = \text{slope of } v\text{-}t, \quad \Delta x = \text{area under } v\text{-}t

Where students slip up

  • Using the equations of motion when acceleration isn't constant. If a depends on t or x, integrate instead.
  • Mixing signs for upward and downward motion. Choose one direction as positive at the start, and keep g negative or positive to match.
  • Confusing displacement with distance. The area under a v-t graph below the axis counts as negative displacement.

Try it on your weakest chapter.

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