05Class 11 Physics

Work, Energy and Power formulas

Work, energy, power and collision formulas. Reach for energy first when a problem cares about speeds and positions and not about time.

Work and energy

Work by a constant force
W=F⃗⋅d⃗=Fdcos⁡θ\displaystyle W = \vec F\cdot\vec d = Fd\cos\theta
Work by a variable force
W=∫xixfF dx\displaystyle W = \int_{x_i}^{x_f} F\,dx
Kinetic energy
K=12mv2=p22m\displaystyle K = \tfrac12 mv^2 = \frac{p^2}{2m}
Work-energy theorem
Wnet=ΔK\displaystyle W_{\text{net}} = \Delta K
Gravitational potential energy
U=mgh\displaystyle U = mgh

Near Earth's surface.

Spring potential energy
U=12kx2\displaystyle U = \tfrac12 kx^2
Spring force
F=−kx\displaystyle F = -kx

Power

Average power
Pav=Wt\displaystyle P_{\text{av}} = \frac{W}{t}
Instantaneous power
P=F⃗⋅v⃗\displaystyle P = \vec F\cdot\vec v

Collisions

Coefficient of restitution
e=v2−v1u1−u2\displaystyle e = \frac{v_2 - v_1}{u_1 - u_2}

e = 1 is elastic, and e = 0 is perfectly inelastic.

1D elastic collision
v1=(m1−m2)u1+2m2u2m1+m2\displaystyle v_1 = \frac{(m_1 - m_2)u_1 + 2m_2u_2}{m_1 + m_2}

Swap the subscripts to get v₂.

Perfectly inelastic collision
v=m1u1+m2u2m1+m2\displaystyle v = \frac{m_1u_1 + m_2u_2}{m_1 + m_2}

Where students slip up

  • Assuming kinetic energy is conserved in every collision. Momentum is conserved, and kinetic energy only in elastic collisions.
  • Using Fd when force and displacement aren't parallel. You need the cos θ.
  • Using mgh for large heights. Far from Earth's surface, use the gravitational form from the next chapters.

Try it on your weakest chapter.

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