All Class 11 Chemistry formulas

The formulas from 4 chapters, in one place to revise from or print. Open a chapter's own sheet to see where students usually slip up.

1. Some Basic Concepts of Chemistry

Mole concept

Moles from mass
n=given massmolar mass\displaystyle n = \frac{\text{given mass}}{\text{molar mass}}
Moles from particles
n=NNA,NA=6.022×1023 mol−1\displaystyle n = \frac{N}{N_A}, \quad N_A = 6.022\times10^{23}\ \text{mol}^{-1}
Moles of a gas at STP
n=V22.4 L\displaystyle n = \frac{V}{22.4\ \text{L}}

Older value. At 1 bar and 273 K, it's 22.7 L.

Mass per cent
mass %=mass of elementmolar mass of compound×100\displaystyle \text{mass \%} = \frac{\text{mass of element}}{\text{molar mass of compound}}\times100

Concentration

Molarity
M=moles of solutelitres of solution\displaystyle M = \frac{\text{moles of solute}}{\text{litres of solution}}
Molality
m=moles of solutekg of solvent\displaystyle m = \frac{\text{moles of solute}}{\text{kg of solvent}}

Doesn't change with temperature.

Mole fraction
xA=nAnA+nB\displaystyle x_A = \frac{n_A}{n_A + n_B}
Dilution
M1V1=M2V2\displaystyle M_1V_1 = M_2V_2

2. Structure of Atom

Light and energy

Wave relation
c=νλ\displaystyle c = \nu\lambda
Photon energy
E=hν=hcλ\displaystyle E = h\nu = \frac{hc}{\lambda}
Photoelectric effect
12mv2=hν−hν0\displaystyle \tfrac12mv^2 = h\nu - h\nu_0

Bohr model

Energy of the nth orbit
En=−2.18×10−18 Z2n2 J\displaystyle E_n = -2.18\times10^{-18}\,\frac{Z^2}{n^2}\ \text{J}
Radius
rn=52.9 n2Z pm\displaystyle r_n = 52.9\,\frac{n^2}{Z}\ \text{pm}
Spectral lines
νˉ=109677(1n12−1n22) cm−1\displaystyle \bar\nu = 109677\left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right)\ \text{cm}^{-1}

Quantum mechanics

de Broglie wavelength
λ=hmv\displaystyle \lambda = \frac{h}{mv}
Heisenberg's uncertainty principle
Δx⋅Δp≥h4π\displaystyle \Delta x\cdot\Delta p \ge \frac{h}{4\pi}
Orbital angular momentum
L=l(l+1) h2π\displaystyle L = \sqrt{l(l + 1)}\,\frac{h}{2\pi}
Nodes
radial=n−l−1,angular=l\displaystyle \text{radial} = n - l - 1, \quad \text{angular} = l
Maximum electrons
in a shell=2n2,in a subshell=2(2l+1)\displaystyle \text{in a shell} = 2n^2, \quad \text{in a subshell} = 2(2l + 1)

5. Thermodynamics

First law

First law
ΔU=q+w\displaystyle \Delta U = q + w

w is the work done on the system.

Expansion work
w=−pextΔV\displaystyle w = -p_{\text{ext}}\Delta V
Reversible isothermal work
w=−2.303 nRTlog⁡V2V1\displaystyle w = -2.303\,nRT\log\frac{V_2}{V_1}
Enthalpy
ΔH=ΔU+ΔngRT\displaystyle \Delta H = \Delta U + \Delta n_gRT
Heat capacities
Cp−CV=R\displaystyle C_p - C_V = R

Thermochemistry

From formation enthalpies
ΔrH∘=∑ΔfHproducts∘−∑ΔfHreactants∘\displaystyle \Delta_rH^\circ = \sum\Delta_fH^\circ_{\text{products}} - \sum\Delta_fH^\circ_{\text{reactants}}
From bond enthalpies
ΔrH=∑BEreactants−∑BEproducts\displaystyle \Delta_rH = \sum\text{BE}_{\text{reactants}} - \sum\text{BE}_{\text{products}}

Note this order is reversed.

Entropy and Gibbs energy

Entropy change
ΔS=qrevT\displaystyle \Delta S = \frac{q_{\text{rev}}}{T}
Gibbs energy
ΔG=ΔH−TΔS\displaystyle \Delta G = \Delta H - T\Delta S

A process is spontaneous when ΔG is negative.

Link to equilibrium
ΔG∘=−2.303 RTlog⁡K\displaystyle \Delta G^\circ = -2.303\,RT\log K

6. Equilibrium

Chemical equilibrium

Equilibrium constant
Kc=[C]c[D]d[A]a[B]b\displaystyle K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}
Kp and Kc
Kp=Kc(RT)Δng\displaystyle K_p = K_c(RT)^{\Delta n_g}
Reaction quotient
Q<K:forward,Q>K:backward,Q=K:at equilibrium\displaystyle Q < K: \text{forward}, \quad Q > K: \text{backward}, \quad Q = K: \text{at equilibrium}

Acids and bases

pH
pH=−log⁡[H+]\displaystyle \text{pH} = -\log[\text{H}^+]
Water
Kw=[H+][OH−]=10−14\displaystyle K_w = [\text{H}^+][\text{OH}^-] = 10^{-14}

At 298 K, so pH + pOH = 14.

Conjugate pairs
Ka×Kb=Kw\displaystyle K_a\times K_b = K_w
Weak acid
α=KaC,[H+]=KaC\displaystyle \alpha = \sqrt{\frac{K_a}{C}}, \quad [\text{H}^+] = \sqrt{K_aC}

For small α.

Acidic buffer
pH=pKa+log⁡[salt][acid]\displaystyle \text{pH} = \text{p}K_a + \log\frac{[\text{salt}]}{[\text{acid}]}
Basic buffer
pOH=pKb+log⁡[salt][base]\displaystyle \text{pOH} = \text{p}K_b + \log\frac{[\text{salt}]}{[\text{base}]}

Solubility

AB type salt
Ksp=s2\displaystyle K_{sp} = s^2
AB₂ type salt
Ksp=4s3\displaystyle K_{sp} = 4s^3
General salt
AxBy:Ksp=xxyysx+y\displaystyle A_xB_y: \quad K_{sp} = x^xy^y s^{x + y}
Precipitation
forms when the ionic product>Ksp\displaystyle \text{forms when the ionic product} > K_{sp}

Try it on your weakest chapter.

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